(6y^2-7y+4)-(3y^2-7y+5)=

Solution for (6y^2-7y+4)-(3y^2-7y+5)= equation:

Simplifying
(6y2 + -7y + 4) + -1(3y2 + -7y + 5) = 0

Reorder the terms:
(4 + -7y + 6y2) + -1(3y2 + -7y + 5) = 0

Remove parenthesis around (4 + -7y + 6y2)
4 + -7y + 6y2 + -1(3y2 + -7y + 5) = 0

Reorder the terms:
4 + -7y + 6y2 + -1(5 + -7y + 3y2) = 0
4 + -7y + 6y2 + (5 * -1 + -7y * -1 + 3y2 * -1) = 0
4 + -7y + 6y2 + (-5 + 7y + -3y2) = 0

Reorder the terms:
4 + -5 + -7y + 7y + 6y2 + -3y2 = 0

Combine like terms: 4 + -5 = -1
-1 + -7y + 7y + 6y2 + -3y2 = 0

Combine like terms: -7y + 7y = 0
-1 + 0 + 6y2 + -3y2 = 0
-1 + 6y2 + -3y2 = 0

Combine like terms: 6y2 + -3y2 = 3y2
-1 + 3y2 = 0

Solving
-1 + 3y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 3y2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 3y2 = 0 + 1
3y2 = 0 + 1

Combine like terms: 0 + 1 = 1
3y2 = 1

Divide each side by '3'.
y2 = 0.3333333333

Simplifying
y2 = 0.3333333333

Take the square root of each side:
y = {-0.577350269, 0.577350269}